To find the kinetic energy of the Ford when its speed is doubled, we need to use the formula for kinetic energy:
K.E = (1/2) * m * v^2
Where:
K.E = Kinetic energy
m = Mass of the Ford
v = Velocity of the Ford
Given that the Ford weighs 1500 kg and is traveling at a speed of 21 m/s, we can substitute these values into the formula to find the initial kinetic energy:
K.E = (1/2) * 1500 kg * (21 m/s)^2
K.E = (1/2) * 1500 kg * 441 m^2/s^2
K.E = 154,350 kg m^2/s^2 (or Joules)
To find the kinetic energy when the speed is doubled, we need to find the new velocity. If the speed is doubled, it becomes 21 m/s * 2 = 42 m/s.
Substituting the new velocity into the formula:
K.E = (1/2) * 1500 kg * (42 m/s)^2
K.E = (1/2) * 1500 kg * 1764 m^2/s^2
K.E = 1,323,000 kg m^2/s^2 (or Joules)
Therefore, when the speed of the Ford is doubled, the kinetic energy increases to 1,323,000 Joules.
If a Ford weighs 1500kg and is traveling at a speed of 21m/s, what is the K.E if the speed of the Ford is doubled?
1 answer
1 answer