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If a force of 80N extends a spring of natural length 8m by 0.4m what will be the length of the spring when the applied force is 100N

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F₁=kx₁
F₂=kx₂
F₁/F₂=x₁/x₂
x₂=x₁F₂/F₁=….
New length is L+ x₂=…

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