If a force of 100n stretches a spring by 0.1find

Question

(1) the elastic constant
(2) the work done in stretching The spring 0.3if the elastic limit is not exceeded

Answer 1

(1)
The elastic constant, also known as the spring constant, can be calculated using Hooke's Law:
F = kx
where F is the force applied, k is the elastic constant, and x is the distance the spring is stretched.

Given:
F = 100N
x = 0.1m

Substitute the values into Hooke's Law equation:
100 = k * 0.1

Solving for k:
k = 100 / 0.1
k = 1000 N/m

Therefore, the elastic constant of the spring is 1000 N/m.

(2)
The work done in stretching the spring can be calculated using the formula:
W = 0.5kx^2

Given:
k = 1000 N/m
x = 0.3m

Substitute the values into the formula:
W = 0.5 * 1000 * (0.3)^2
W = 0.5 * 1000 * 0.09
W = 45 J

Therefore, the work done in stretching the spring by 0.3m is 45 Joules if the elastic limit is not exceeded.