IF A FORCE OF 100N STRETCHES A SPRING 0.1CM, FIND THE DONE IN STRETCHING THE SPRING 0.03CM . IF THE ELASTIC LIMIT IS NOTEXCEEDED?

Answer 1

F = k x
100 = k * 0.001 m
k = 10^5 N/meter
work = (1/2) k x^2 = (1/2) * 10^5 * (3 *10^-4 m)^2
= (1/2)(9) (10^-3) = 4.5 * 10^-3 Joules