If a fighter jet touches the runway at 220km/h, then decides to brake, and finally comes to a stop at 31 seconds later.

What is the shortest runway the fighter jet can land, assuming constant deceleration starting at touchdown?

Is the answer 570 meters or am I just totally off

1 answer

1) change speed to m/s
61.1m/s check that.

avgspeed=(vf+vi)/2=30.5m/s

distance=avgspeed*time

I get considerably more than you

Remember, under constant deaccleration to a stop, the average speed is 1/2 the initial speed.