I will do of these,
for 135° :
assume the axle is 20.5 above the ground
height above axle:
sin135 = h/20.5
h = 20.5sin135 = appr 14.5 m
so height above the ground = 20.5 + 14.5 = 35
for 315°
height from axle :
sin 315 = h/20.5
h = 20.5sin135 = appr - 14.5
notice the position would be BELOW the axle
so height above ground = 20.5 - 14.5 = 6 m
If a ferris wheel with a 20.5 meter radius, how high would one car be from the loding dock at these given angles trveled by the rider?:
90
135
180
225
270
315
405
450
495
and 540?
1 answer