Of course you know where to start. Draw a picture!
You're clearly going to have to tip the entertainment center. So, suppose the bottom corner is x from one side of the door, and y from the other side.
On the x side, the base of the e.c. reaches up to a height z. Since the height of the e.c. is 60", it will reach up (5/4 z) high. So, now you just have to solve
x+y=35
x^2+z^2 = 48^2
y^2+(5/4 z)^2 = 60^2
Do that and you will find that
(x,y,z) = (15.55,19.44,45.41)
The e.c. will fit exactly at that point. Chances are, there's a bit of wiggle room as well.
I must say, a 48" deep e.c. is some cabinet!
If a door measures 78in tall by 35in wide will an entertainment center measuring 60in x 48in x 48in fit through it? Im not even sure where to start!
5 answers
Well, that solution won't work, because the top corner of the tipped e.c. is higher than 73".
So, I think it will not fit.
So, I think it will not fit.
What if it was 48in high?
Oh, yeah. I didn't think of tipping it on its side first. Well, try the same equations, but substituting in 48 for 60.
Good catch.
Good catch.
Ok. How about this.
If the e.c. is tipped up at an angle x, we need
48cos(x) + 48sin(x) <= 35
48√2 cos(π/4 - x) <= 73
Now, the e.c. just fits across when x = 10.4°
So, any angle higher than that will still fit, since the top corner will never be higher than 48√2 = 67.88" high
If the e.c. is tipped up at an angle x, we need
48cos(x) + 48sin(x) <= 35
48√2 cos(π/4 - x) <= 73
Now, the e.c. just fits across when x = 10.4°
So, any angle higher than that will still fit, since the top corner will never be higher than 48√2 = 67.88" high