If a diagnol for a rectangle ABCD was measured to be 20 and a square was put in it slanted(looking like a rhombus). This rhombus is called EFGH. Prove find the perimeter of EFGH. (IT IS EASIER TO DRAW IT THEN SOLVE IT =))

Answer 1

I can only speak for myself of course, but I can't figure out what your diagram would look like.
What do you mean by "a square was put in it"?
Where does the square touch ?

Answer 2

on the sides of the square touching and bisecting each side

Answer 3

So the original "rectangle" was also a square ?

Answer 4

No the square inside touches the rectangle on the outside.

Answer 5

I concluded that your problem deals with the midpoint-parallel theorem
that is, "a line joining the midpoints of two sides of a triangle is parallel to the third side and one half its length
So each side of the inside rhombus is 1/2 the diagonal.
There are 4 sides, so their total length is twice the diagonal of the rectangle or
2(20) = 40

BTW, if the original is not a square, then the inside figure also cannot be a square. That is where the confusion arises in your problem, and that is whay nobody answered it. Often questions that are worded in a confusing or contradictory way are left unanswered.

Answer 6

k thanks Reiny