2NaOH + H2SO4 ==> Na2SO4 + 2H2O
moles NaOH = M x L = ?
Look at the equation. moles H2SO4 = 1/2 * moles NaOH.
Then MH2SO4 = moles H2SO4/L H2SO4.
Solve for M H2SO4.
If a chemist titrates 300.0 mL of H2SO4 with a 3.0 M solution of NaOH and requires only 3.4 mL of the base to reach the endpoint, what is the concentration of the sulfuric acid?
1 answer