Asked by Jill
If a catapault throws a tennis ball at an intial velocity of 13 m/s, at what angle will it need to throw the ball to hit a target 40 ft away?
Answers
Answered by
drwls
First of all, convert to meters. 40 m = 12.19 m
The time of flight T must be such that
12.19 m = 13 m/s cos A * T
T also must satisfy (from the vertical equation of motion)
(T/2) g = 13 m/s * sin A
If you divide one equation by the other you can get an equation for tan A and eliminate the T unkonown.
The time of flight T must be such that
12.19 m = 13 m/s cos A * T
T also must satisfy (from the vertical equation of motion)
(T/2) g = 13 m/s * sin A
If you divide one equation by the other you can get an equation for tan A and eliminate the T unkonown.
Answered by
Jill
I am still lost...a little more help please!
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