If a box can hold 28 1/8 kilograms, how many 1 7/8 kilogram books will it hold? (1 point) Responses 15 books 15 books 35 books 35 books 48 books 48 books 52 books

Answer 1

To determine how many \(1 \frac{7}{8}\) kilogram books can fit in a box that holds \(28 \frac{1}{8}\) kilograms, we will first convert both mixed numbers into improper fractions.

1. Convert \(28 \frac{1}{8}\) to an improper fraction:

\[ 28 \frac{1}{8} = \frac{28 \times 8 + 1}{8} = \frac{224 + 1}{8} = \frac{225}{8} \]

2. Convert \(1 \frac{7}{8}\) to an improper fraction:

\[ 1 \frac{7}{8} = \frac{1 \times 8 + 7}{8} = \frac{8 + 7}{8} = \frac{15}{8} \]

3. Now, divide the total weight the box can hold by the weight of one book:

\[ \text{Number of books} = \frac{28 \frac{1}{8}}{1 \frac{7}{8}} = \frac{\frac{225}{8}}{\frac{15}{8}} = \frac{225}{8} \times \frac{8}{15} = \frac{225}{15} = 15 \]

Thus, the box can hold 15 books.