if a box can hold 28 1/8 how many 1 7/8 kilogram books will it hold

Answer 1

To find out how many books weighing $1\frac{7}{8}$ kilograms can fit in a box that holds $28\frac{1}{8}$ kilograms, we need to first convert the mixed numbers to improper fractions or decimals.

1. Convert $28\frac{1}{8}$ to an improper fraction: $$28\frac{1}{8}=\frac{28\times 8+1}{8}=\frac{224+1}{8}=\frac{225}{8}$$

2. Convert $1\frac{7}{8}$ to an improper fraction: $$1\frac{7}{8}=\frac{1\times 8+7}{8}=\frac{8+7}{8}=\frac{15}{8}$$

3. Now, divide the total weight the box can hold by the weight of one book: $$\text{Number of books}=\frac{28\frac{1}{8}}{1\frac{7}{8}}=\frac{\frac{225}{8}}{\frac{15}{8}}=\frac{225}{8}\times \frac{8}{15}=\frac{225}{15}=15$$

So, the box can hold 15 books weighing $1\frac{7}{8}$ kilograms each.