6 * 13 = 78 square inches for each tile
8500 / 78 = 108.97 = 109 tiles
If a. Bathroom area is 8500 inches. And the tiles are 6 by 13ins, what's the least amount of tiles needed to cover area?
2 answers
Unrealistic question.
Of course the minimum number of tiles would be obtained when the shape is as close to a square as possible, but we can't control the shape of the region based on the number of tiles. (The architect had decided the shape, perhaps it is not even rectangular )
Anyway .....
let the sides be x by y inches
xy = 8500
number of tiles = (x/6)(y/13) = xy/78 = 8500/78
= 108.9
.= 109 (using .= to mean appr =)
e.g. suppose 8500 = 100 by 85
using 100/6 tiles along the longer side = 16.66..
so let's say 17 tiles, with the last row to be cut
using 85/13 tiles along the longer side = 6.5 or 7 tiles, with the last row to be cut.
so we need 17x7 or 119 tiles.
Suppose we lay the tiles in alternate patterns, so we get 4 tiles to form a square of 19 by 19
then each grouping has a area of 361 in^2
so we need 8500/361 = 23.54 groupings
that is we need 24 groupings of 4 or 96 tiles
ok, so we would need (x/19) tiles along one side and (y/19) tiles
along the other side.
Assuming the area is square
then each side of the floor = √8500 = 92.195
92/6 = 15.33 , so we need 16 along that side
92/13 = 7.07 , so we need 8 along that side
number of tiles = 8x16 or 128
Assuming the area is made up of 170 by 50
using the longer side of tile along the longer side of the floor, we need 170/13 or 14 tiles, cutting needed for the last row
As you can see, more information is needed to get an actual answer
Of course the minimum number of tiles would be obtained when the shape is as close to a square as possible, but we can't control the shape of the region based on the number of tiles. (The architect had decided the shape, perhaps it is not even rectangular )
Anyway .....
let the sides be x by y inches
xy = 8500
number of tiles = (x/6)(y/13) = xy/78 = 8500/78
= 108.9
.= 109 (using .= to mean appr =)
e.g. suppose 8500 = 100 by 85
using 100/6 tiles along the longer side = 16.66..
so let's say 17 tiles, with the last row to be cut
using 85/13 tiles along the longer side = 6.5 or 7 tiles, with the last row to be cut.
so we need 17x7 or 119 tiles.
Suppose we lay the tiles in alternate patterns, so we get 4 tiles to form a square of 19 by 19
then each grouping has a area of 361 in^2
so we need 8500/361 = 23.54 groupings
that is we need 24 groupings of 4 or 96 tiles
ok, so we would need (x/19) tiles along one side and (y/19) tiles
along the other side.
Assuming the area is square
then each side of the floor = √8500 = 92.195
92/6 = 15.33 , so we need 16 along that side
92/13 = 7.07 , so we need 8 along that side
number of tiles = 8x16 or 128
Assuming the area is made up of 170 by 50
using the longer side of tile along the longer side of the floor, we need 170/13 or 14 tiles, cutting needed for the last row
As you can see, more information is needed to get an actual answer
1 answer