t=19.6/2
v=5 * 9.8
=49 m/s
If a ball that is freely falling has attained a velocity of 19.6 m/s after two seconds, what is its velocity five seconds later?
6 answers
Nope. Sorry J.
7*9.8=68.6
7*9.8=68.6
@Chanz, oops my bad, you are correct.
Vf-19.6 m/s= (9.8 m/s/s)(5 s)
Vf-19.6 m/s = 49 m/s
Vf= 68.6 m/s
Vf-19.6 m/s= (9.8 m/s/s)(5 s)
Vf-19.6 m/s = 49 m/s
Vf= 68.6 m/s
forgot that last calculation :)
wait so i did 9.8 times 5 and got 49, is that the final answer? and how did you guys get 68.6 and what does that number mean?
nope, you forgot acceleration (a)
a=vf (final velocity) - vi (initial velocity) divided by t (time)
the acceleration of a free falling body is 9.8 m/s/s due to the force of gravity.
9.8 m/s/s=vf-19.6m/s / 7s
if you multiply both sides by 7, you get
68.6 m/s/s=vf-19.6 m/s
then you add 19.6 to both sides and you get
88.2 m/s/s= vf
so the final velocity (the answer) is equal to 88.2 m/s/s
correct me if I'm wrong but I think that's how you do it
a=vf (final velocity) - vi (initial velocity) divided by t (time)
the acceleration of a free falling body is 9.8 m/s/s due to the force of gravity.
9.8 m/s/s=vf-19.6m/s / 7s
if you multiply both sides by 7, you get
68.6 m/s/s=vf-19.6 m/s
then you add 19.6 to both sides and you get
88.2 m/s/s= vf
so the final velocity (the answer) is equal to 88.2 m/s/s
correct me if I'm wrong but I think that's how you do it
1 answer