time in flight: solve s(t) = 0
max height at the vertex: t=3
v = 96-32t
If a ball is thrown vertically upward from the roof of 48 foot building with a velocity of 96 ft/sec, its height after t seconds is s(t)=48+96t−16t^2. What is the maximum height the ball reaches?
What is the velocity of the ball when it hits the ground (height 0)?
2 answers
the max height is on the axis of symmetry of the parabola
... t = -b / 2a ... -96 / (2 * -16)
... plug into the equation to find s
velocity is ds/dt
... solve for t when s is zero
... plug into the 1st derivative of s(t)
... t = -b / 2a ... -96 / (2 * -16)
... plug into the equation to find s
velocity is ds/dt
... solve for t when s is zero
... plug into the 1st derivative of s(t)
1 answer