a. use the equation given, h(t)=0, so
0=30+25t-5t^2 solve for t.
h domain is zero to max height
max height will be when velocity is zero (at top)
V=25-10t but v is zero, solve for t at max height, then put that t in the original h(t) equation.
If a ball is thrown upward from a building 30 m tall and the ball has a vertical velocity of 25 m/s, then its approximate height above the ground t seconds later is given by h(t) = 30 + 25t - 5t^2
a. After how many seconds does the ball hit the ground?
b. What is the domain of h?
c. How high does the ball go?
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