a = - 9.8 m/s^2
v = Vi + a t = 0 - 9.8 t
h = Hi + Vi t -(9.8/2) t^2
0 = Hi + 0 (3) - (9.8/2)(3)^2
4.9 (9) = Hi
Hi = 44.1 meters high
if a ball is thrown horizontally from the top of a cliff and takes 3 seconds to reach the beach below. calculate the height of the cliff by considering the vertical motion only.
answer : s=ut+half at(square)
s=0*3+half*10*3
s=3+45
s=48 m/s(square)
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