If a ball is kicked at 35 degrees above the horizontal, what is the speed to barely clear the 3m tall goal post 60m away?

Answer 1

use the formula for dynamics

y=xtanθ-(gx^2)/(2V^2Cos^2(θ))

where:
θ=35
g=9.81 m/s^2
x=60 m
y=3 m
V=initial speed

just plug-in the value.. :D