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if a+b=3 and a^2+b^2=6, what is a^3 + b^3
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ab=((a+b)²-(a²+b²))/2
S=a^3+b^3
=(a+b)(a²-ab+b²)
=(a+b)(a²+b² - ((a+b)²-(a²+b²))/2))
All terms in the innermost parentheses are known, hence S.
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