Dispersal forces travel equally in 3 diameter length vectors.
F1=<9.8><s>[60N]
F2=<9.8><s^2>[120N]
F3=<9.8><s^3>{180N}
Here's where it gets tricky.
Derive the hollow balls diameter from the force:
3F^8(9.8)/Gb[1.333]^W
3F^8=Gb^w(15.66)
Gb^w{180^3x)(120^2y)(60z)+C
[460xyz^6)=d^(1/8)
d=12m
r=6m
ri=5.7m
ContinDisperse=ri^12(F1F2F3)
=900N
900(3)
2700N
If a 60N weight free falls onto a hollow ball what amounts of force are produced after 3 seconds of impact, if it lands .3m away of the center?
2 answers
Thank you!!!!