If a 54 pound boy falls off the top of the grand canyon which is 5996 feet deep, how many seconds will it take for him to hit the bottom?

Answer 1

his weight is not a factor

the free fall equation is ... h = -1/2 g t^2 + Vo t + Ho
... h is height , g is gravitational acceleration
... Vo is initial velocity , Ho is initial height

h = 0 at the bottom , g = 32 ft/s^2

0 = -16 t^2 + 0 t + 5996

solve the quadratic for t

Answer 2

0.5g*t^2 = 5996.
16t^2 = 5996,