just substitute in. For example,
ABC = (3x+4)(x^2+2)(x^2+3x-2)
= 3x^5+13x^4+12x^3+18x^2+12x-16
what do you get for the others?
If A=3x+4 and B=x^2+2 and C=x^2+3x-2, find the following:
1. AC+B
2. (A+B)(B-C)
3. ABC
3 answers
1. 17x^2+6x-6
2. 3x^3+9x^2+18x
did you get the same?
2. 3x^3+9x^2+18x
did you get the same?
I get
AC+B = 3x^^3+14x^2+6x-6
AC has to be 3rd degree, since A is 1 and C is 2
(A+B)(B-C)
= -3x^3-5x^2-6x+24
Somewhere you're messing up. Visit calc101.com and click on the "long multiplication" link, and it will show all the details of polynomial multiplication.
AC+B = 3x^^3+14x^2+6x-6
AC has to be 3rd degree, since A is 1 and C is 2
(A+B)(B-C)
= -3x^3-5x^2-6x+24
Somewhere you're messing up. Visit calc101.com and click on the "long multiplication" link, and it will show all the details of polynomial multiplication.
1 answer