if a 250 g mass is placed at the 20 cm mark (30 cm from the fulcrum), at what mark should a 500 g mass be placed so that the system balances?

Answer 1

I assume the fulcrum is at the center of a 100-cm bar. If so, then
250*30 = 500*15
so, the heavy weight is 15cm on the other side of the fulcrum, at the 65-cm mark.

If the fulcrum is not at the center of the bar, then you have to adjust for the difference in mass of the bar on each side.

Answer 2

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