If a 20g bullet traveling 910m/s strikes an 80kg man wearing a safety vest how fast in m/s will the man be knocked backwards
2 answers
The man will be knocked backwards at a speed of approximately 0.2 m/s.
initial momentum = 0.020 * 910 = 18.2 kg m/s
final momentum the same
18.2 = (80 + .020) v
v = 0.228 m/s
final momentum the same
18.2 = (80 + .020) v
v = 0.228 m/s
2 answers