.........A <==> 2B
I......2.30M.....0
C........-x......2x
E......2.30-x....2x
Kc = 5.04E-6 = (B)^2/A
Substitute the E line into Kc expression I have above and solve for x.
Then 2x = (B)
If a 2.30 M sample of A is heated to 500 K, what is the concentration of B at equilibrium?
A<-> 2B
Kc= 5.04x10^-6 at 500k
2 answers
Thanks!