If a 10k ohm and a 5k ohm resister are connected in series across a 12 volt source whats the voltage across the 10k ohm resistor and 5 ohm resistor?

Answer 1

since they are in series, the voltage drop is divided up into

2/3 across the 10k
1/3 across the 5k

since R = R1+R2 = 5+10 = 15 k, and
10 is 2/3 of 15, 5 is 1/3 of 15.

Answer 2

V = 12 Volts.
R1 = 10k Ohms.
R2 = 5k Ohms.

I = V/(R1+R2) = 12/(10k+5k) = 0.8 mA.

V1 = I*R1 = 0.8mA * 10k = 8 Volts.

V2 = I*R2 = 0.8mA * 5k = 4 Volts.

Answer 3

Find the net force on Q4 if Q1 = 6micro-C, Q2 = -3micro-C, Q3 = 7 micro-C and Q4 = 5 micro-C. The four charges forms a rectangular shape. The distance of separation, Q1 to Q2 = 0.2 meter, Q2 to Q4 = 0.1 meter, Q2 to Q3 = 0.2 meter and Q3 to Q1 = 0.1 meter. Give your answers in two significant figures, for both the magnitude and direction. Separate them by a comma , Ex. 45N, 25 degrees.