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If 9th term of an arithmetic progression is 0, prove that its 29th term is double the 19th term.

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If the 9th term of an AP is 0 , then
a+8d = 0
a = -8d

29th term = a + 28d
= -8d + 28d = 20d

19th term = a +18d
= -8d + 18d = 10d

since 20d = 2(10d)
the 29th term is twice the 19th term

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