The average force over the 9-10 cm interval is 900 N. Since force is linear with length (x), that means the force is 900 N at x = 9.5 cm.
Similarly, the force is 1500 N at x = 10.5 cm.
Those two points in an F = mx + b curve can be fit with
F = 600 (x - 8 cm) N
F = 0 when x = 8 cm, so that is the natural length of the spring.
The spring constant is 600 N/cm
If 9 J of work are needed to stretch a spring from 9 cm to 10 cm and 15 J are needed to stretch it from 10 cm to 11 cm, what is the natural length L of the spring?
2 answers
how did you get the 8cm?