if 9^2-x and 3x-1/2y = 13/2,find the value of x+3y

Answer 1

To find the value of x + 3y, we need to solve the system of equations:

1) 9^2 - x = 13/2
2) 3x - (1/2)y = 13/2

Let's start by solving equation 1 for x:
9^2 - x = 13/2
81 - x = 13/2
Multiply both sides by 2 to clear the fraction:
162 - 2x = 13
Subtract 162 from both sides:
-2x = -149
Divide both sides by -2:
x = 149/2

Now substitute this value of x into equation 2) and solve for y:
3(149/2) - (1/2)y = 13/2
447/2 - (1/2)y = 13/2
Subtract 447/2 from both sides:
-(1/2)y = -434/2
Divide both sides by -(1/2) or multiply by -2:
y = -434

Now, we can find the value of x + 3y:
x + 3y = (149/2) + 3(-434)
x + 3y = 149/2 - 1302/2
x + 3y = -1153/2