In AP n-th term:
an = a + ( n - 1 ) d
where
a = first term
d = common difference
a1 = a
a2 = a + d
a3 = a + 2 d
a4 = a + 3 d
In this case:
a1 = a = 8
a4 = a + 3 d = - 4
8 + 3 d = - 4
Subtract 8 to both sides
3 d = - 12
d = - 12 / 3
d = - 4
x = a2 = a1 + d = 8 + ( - 4 ) = 8 - 4 = 4
y = a3 = a1 + 2 d = 8 + 2 ∙ ( - 4 ) = 8 - 8 = 0
x = 4 , y = 0
Your AP is:
8 , x , y , - 4
8 , 4 , 0 , - 4
If 8,x,y,-4 are in A.P
1 answer