If 75.0 mL of an AgNO3 solution reacts with enough Cu to produce .25g Ag by single displacement, what is the molarity of the initial AgNO3 solution if Cu(NO3)2 is the other product?

Answer 1

Write the equation and balance it.
M Ag = moles/L. Plug and chug.

Answer 2

Im Lost i wrote the equation but what do i do next?
2AgNO3+Cu=2Ag+Cu(NO3)2

Answer 3

I gave you the equation and you don't need the equation. I just wanted to make sure you knew how to write it.
moles Ag = 0.25 g/atomic mass.
M = moles/L.
You get calculate the moles Ag deposited. Then M = moles/L.