Question

If 75.0 mL of an AgNO3 solution reacts with enough Cu to produce .25g Ag by single displacement, what is the molarity of the initial AgNO3 solution if Cu(NO3)2 is the other product?

Answer 1

Write the equation and balance it.
M Ag = moles/L. Plug and chug.

Answer 2

Im Lost i wrote the equation but what do i do next?
2AgNO3+Cu=2Ag+Cu(NO3)2

Answer 3

I gave you the equation and you don't need the equation. I just wanted to make sure you knew how to write it.
moles Ag = 0.25 g/atomic mass.
M = moles/L.
You get calculate the moles Ag deposited. Then M = moles/L.