q = mc*delta T
q = heat = 72,400J
m = 752g
c = specific heat = ?
dT = 9.95
Solve for c.
If 72.4 kJ of heat is supplied to a 752 g block of metal, the temperature of the metal increases by 9.95°C. Calculate the specific heat capacity of the metal in J/g·°C.
I cannot find the information in my textbook, and I don't understand the equation needed to do the work on the summer assignment...
2 answers
q = mcdT
72 400 = 752 X C X 9.95
C = 9.676 J/C
72 400 = 752 X C X 9.95
C = 9.676 J/C
1 answer