If 700 grams of glucose (C6H12O6) are fermented, what is the maximum volume in milliliters of ethanol (C2H5OH) that can form? (Density of ethanol is 0.79 g/mL)

Question

If 700 grams of glucose (C6H12O6) are fermented, what is the maximum volume in milliliters of ethanol (C2H5OH)  that can form? (Density of ethanol is 0.79 g/mL)

abigail · Answer

The fermentation of glucose to form ethanol occurs according to the following chemical reaction: C6H12O6(aq) → 2 C2H5OH(l) + 2 CO2(g)

DrBob222 · Answer

C6H12O6(aq) → 2 C2H5OH(l) + 2 CO2(g)
mols glucose = grams/molar mass = ?
mols ethanol = 2x that (look at the coefficients in the balanced equation).
g ethanol = mols ethanol x molar mass ethanol.
Convert to mL. volume in mL = grams/density.