If 7 mL of water is added to 3 mL of a 0.50 M KOH solution, the concentration of KOH is changed to?

Question

I am not sure how to go about doing this. Please help, thank you!!!

Would I do (7)(3) / 0.50?

Answer 1

Assuming the volume will add to give a final volume of 10 mL (technically they will not), then the new M is
0.50 x (3/10) = ?

Answer 2

Oh ok thank you!