If 6, p and 14 are consecutive terms in arithmetic progression(A.P) Find the value of p

Answer 1

(14 - 6) / 2 = p

Answer 2

I think she meant p = (6+14)/2 = 10
the middle term is the average of the other two.

This is because the difference is constant. That is, p-6 = 14-p

Answer 3

Oops! You're right, oobleck!

Answer 4

Let first term= a
second term= T2
third term= T3
nth term= Tn
common differnce= d
So, a= 6
T2= P
T3= 14
d= ?
Tn= a + (n - 1)d
T2= a + (2 - 1)d= P
= a + d= P
= 6 + d= P
T3= a + (3 - 1)d= 14
= a + 2d= 14
= 6 + 2d= 14
= 2d= 14 - 6
= 2d= 8
= d= 8/2= 4
= d= 4

Thus, from T2,
6 + d= P (d= 4)
6 + 4= P
10= P
P= 10

Answer 5

Answer:10