balance the equation;
C5H12+ 8O2 >>> 5CO2 + 6H2O
so you get 5x the number of moles you used of Pentane.
If 6.64 moles of C5H12 reacts with excess O2, how many moles of CO2 will be produced in the following combustion reaction?
Can plz explain how to do it
Thank You
5 answers
I do not see your reaction.
I will assume:
1 C5H12 + 8O2 --> 5CO2 + 6H2O
so
6 molecules or mols of C5H12
gives
6*5 = 30 molecules or mols of CO2
I will assume:
1 C5H12 + 8O2 --> 5CO2 + 6H2O
so
6 molecules or mols of C5H12
gives
6*5 = 30 molecules or mols of CO2
How do you get 6 molecules or mols of C5H12
I mean how did you get the number 5
The whole numbers on teach compound tells you the mole ratios..
0 answers