Asked by Whitney

If 507 g FeCL2 were used up in the reaction FeCL2 + 2NaOH > Fe(OH)@(s) + 2NaCL, how many grams of Fe(OH)2 would be formed?
Answered by DrBob222
mols FeCl2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols FeCl2 to mols Fe(OH)2.
Now convert mols Fe(OH)2 to grams. g = mols x molar mass = ?
Answered by Anonymous
654
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