To answer this question, we need to determine the balanced chemical equation for the reaction between magnesium (Mg) and bromine (Br).
The balanced chemical equation is:
2 Mg + Br2 -> 2 MgBr
From the balanced chemical equation, we can see that for every 2 moles of magnesium reacted, we produce 2 moles of magnesium bromide (MgBr).
To find the mass of the products, we need to calculate the number of moles of magnesium (Mg) and bromine (Br) that are reacting.
Given:
Mass of magnesium (Mg) = 50 g
Mass of bromine (Br) = 30 g
To calculate the number of moles, we use the formula:
Number of moles = mass / molar mass
The molar mass of magnesium (Mg) is approximately 24.31 g/mol
The molar mass of bromine (Br) is approximately 79.90 g/mol
Number of moles of magnesium (Mg) = 50 g / 24.31 g/mol ≈ 2.06 mol
Number of moles of bromine (Br) = 30 g / 79.90 g/mol ≈ 0.38 mol
According to the balanced chemical equation, the ratio of magnesium (Mg) to magnesium bromide (MgBr) is 1:1. This means that for every 2 moles of magnesium (Mg) reacted, we produce 2 moles of magnesium bromide (MgBr).
Since we have 2.06 moles of magnesium (Mg), we can expect to produce 2.06 moles of magnesium bromide (MgBr) as well.
The molar mass of magnesium bromide (MgBr) is approximately 184.11 g/mol.
Mass of magnesium bromide (MgBr) = number of moles × molar mass
= 2.06 mol × 184.11 g/mol
≈ 378.77 g
Therefore, the mass of the products (magnesium bromide) is approximately 378.77 g.
The correct answer is not listed among the provided options.
If 50 g of Magnesium(Mg) is reacted with 30 g of Bromine(Br), what is the mass of the products?
a
30 g
b
20 g
c
50 g
d
80 g
1 answer