Asked by Adam -Please check if I'm Correct
If 50 ft lbs of work is done on the same spring (in part a) in order to compress it, by how much is the spring shortened?
*Information on part (a) is 400 #/in is the k constant and 1.75" is the compression.
50 ft lbs = 600 in lbs
equation is: 1/2 * 600" lb * 1.75"^2 = 918.75 lbs???
I'm looking for the length in this question, how do I get that?
*Information on part (a) is 400 #/in is the k constant and 1.75" is the compression.
50 ft lbs = 600 in lbs
equation is: 1/2 * 600" lb * 1.75"^2 = 918.75 lbs???
I'm looking for the length in this question, how do I get that?
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