If 50.00mL of 1.10M NaOH is added to 25.00mL of 1.86M HCl, with both solutions originally at 24.70 degrees Celsius, what will be the final solution temperature? (Assume that no heat is lost to the surrounding air and that the solution produced in the neutralization reaction has a density of 1.02g/mL and a specific heat of 3.98J/g*degrees Celcius.)
Express answer in four significant figures.
The heat of neutralization is -55.84 kJ/mol H20 produced.
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