If 50.0 mL of a 0.10M solution of sodium chloride is mixed with 50.0 mL of 0.10 M magnesium chloride, what is the molar concentration of chloride in the resulting solution?

Answer 1

There will be 0.1 x 0.05 = 0.005 moles of Cl- from NaCl and 0.1x0.05x2 = 0.010 moles of Cl- from MgCl2 in the resulting 0.10 L of mixture. That is 0.015/0.1 = 0.15 moles per liter. Looks like 0.15 M is the answer.