I read that as exactly 15 of the 200 to be defective
= C(200,15)( .05)^15 (.95)^185
= .0337.. or their answer of .034
Wow, those were some very large and very small numbers,
good thing my calculator has more than one memory location.
If 5% of the bolts made by an automotive factory are defective , what is the probability that in a shipment of 200 bolts, there are 15 defective bolts?
Use the binomial probability formula
n=200 and p = 0.05
a. 0.081
b. 0.034
c. 0.313
d. 0.054
4 answers
Yeah, is 15 defective, sorry for the question mark
Thank You!
200C15 .95^185 .05^15