If 5.20 g of HCl is added to enough distilled water to form 3.00 L of solution, what is the molarity of the

Question

solution? [Use molecular weight: HCl, 36.46 amu]

Answer 1

Molarity = moles of solute / Liters of solution
moles = mass given / molar mass
substituting,
Molarity = (5.20/36.46)/3
Molarity = 0.0475 M

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