If 465 cm³ of sulphur(IV)oxide,can be diffuse through porous partition in 30s how long will(a) an equal volume , (b)620cm³ of hydrogen sulphide take to diffuse through the same partition ?(H=1,S=32,O=16)

Answer 1

part a.
mm = molar mass
(rate 1)/(rate 2) = sqrt (mm 2/mm 1)
Substitute the following:
rate 1 = rate SO2 = 465 cc/30 sec
rate 2 = rate H2S = 465 cc/x sec
mm 1 = molar mass SO2 = 64
mm 2 = molar mass H2S = 34
Solve for x sec.
part b. Substitute the new numbers.
Post your work if you get stuck.

Answer 2

Pls I am confused
I don't understand

Answer 3

I dont understand.please go straight to the point😢

Answer 4

how will I substitute the new answer please I am confused please explain more

Answer 5

I am confused about the answer to the question above

Answer 6

I am confuse, explain more

Answer 7

I am confused

Answer 8

Please l dont understand go straight to the point and make your explanation clear

Answer 9

th2/to2=√mo2/mo2