You must mean SO2. I assume that is sulfur (iv) oxide.
a makes no sense. "an equal volume of what"
b.
(rate1/rate2) = sqrt (mass 2/mass 2)
(465/30)/(620/sec) = sqrt(mass H2S/mass SO2)
Substitute the numbers and solve for seconds.
Post your work if you get stuck.
If 465 cm cube of sulphur (I've) oxide can diffuse through porous partition in 30 seconds, how long will
a. An equal volume
b. 620 cm cube of hydrogen sulphide take to diffuse through the same partitio ( h = 1, s = 32 , 0 = 16)
2 answers
t2 =t1×sqrt m1÷sqrt m2