To find out how many pounds of grass seed are needed to cover 290 square feet, we can start by determining the coverage per pound of grass seed from the initial information provided.
If 4 pounds of grass seed covers 92 square feet, then:
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Find the coverage per pound: \[ \text{Coverage per pound} = \frac{92 \text{ square feet}}{4 \text{ pounds}} = 23 \text{ square feet per pound} \]
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Now, we need to find how many pounds are needed to cover 290 square feet: \[ \text{Pounds needed} = \frac{290 \text{ square feet}}{23 \text{ square feet per pound}} \approx 12.61 \text{ pounds} \]
Since you cannot buy a fraction of a pound, round up to the nearest whole pound, which would be 13 pounds.
Thus, the answer is 13 pounds.
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