If 4-jx-x^2 is divided by x-4 the remainder is -4. Find k.
2 answers
I meant find j
a little synthetic division shows that
(-x^2-jx+4) / (x-4)
leaves a remainder of -4j+12
So, we need j = 3
-x^2-3x+4 = (-x+1)(x+4)
(-x^2-jx+4) / (x-4)
leaves a remainder of -4j+12
So, we need j = 3
-x^2-3x+4 = (-x+1)(x+4)
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