if 4.35 kj of energy are needed to heat a sample of water from 62C into steam at 100.0C what is the mass of the sample

Answer 1

q1 - heat needed to go from 62 C to 100 C.
q1 = mass H2O x specific heat H2O x (Tfinal-Tinitial). Tf is 100 and Ti is 62.

q2 is heat needed to convert the sample of water at 100 to steam at 100.
q2 = mass H2O x heat vaporization.

So q1 + q2 = 4350 J
I show q1 above and q2 above. Set up the equation, mass H2O is the unknown you're looking for. You will need to look up specific heat H2O and heat vaporization if you don't already know it. Remember to keep the units straight; i.e., I've changer the 4.35 kJ to J. I suggest you keep everything in J. Post your work if you get stuck.

q2 =