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If 3x+2y=12 and xy=6,find 27x^3+8y^3

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write it in form of a^3+b^3 as (3x)^3 + (2x)^3 now apply identity and open it
27x^3+8y^3 = (3x+2y)(9x^2-6xy+4y^2)
(3x+2y)^2 = 144 = 9x^2+12xy+4y^2
. . .
done yesterday

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