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If 360 mL of 2.47 M aqueous NaI and 212 g of Pb(NO3)2 are reacted stoichiometrically according to the balanced equation, how many milliliters of 4.62 M aqueous NaNO3 are produced?

Pb(NO3)2(aq) + 2NaI(aq) �¨ PbI2(s) + 2NaNO3(aq)

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i figured it out...nvm

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